Distance between Teruel and Waterbury

The distance between Teruel (Aragon, Spain) and Waterbury (Connecticut, USA) is ca. 5.857,3 km (air line).

Teruel

Latidute: 40.34252189
Longitude: -1.10641532

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Teruel and other cities and places worldwide

Distance between Teruel and other major cities