Distance between San Miguelito and Waterbury

The distance between San Miguelito (Panama) and Waterbury (Connecticut, USA) is ca. 3.668,8 km (air line).

San Miguelito

Latidute: 9.05545622
Longitude: -79.49287641

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between San Miguelito and other cities and places worldwide

Distance between San Miguelito and other major cities