Distance between Salamanca and Waterbury

The distance between Salamanca (Castile and León, Spain) and Waterbury (Connecticut, USA) is ca. 5.480,3 km (air line).

Salamanca

Latidute: 40.961612
Longitude: -5.667606

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Salamanca and other cities and places worldwide

Distance between Salamanca and other major cities