Distance between Aracaju and Waterbury

The distance between Aracaju (Sergipe, Brazil) and Waterbury (Connecticut, USA) is ca. 6.896,0 km (air line).

Aracaju

Latidute: -10.90954211
Longitude: -37.07477321

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Aracaju and other cities and places worldwide

Distance between Aracaju and other major cities