The distance between Yekaterinburg (Russia) and Jacksonville (Florida, USA) is ca. 9.692,0 km (air line).
Distance between Yekaterinburg and other cities and places worldwide
Distance between Yekaterinburg and other major cities
Los Angeles9908 km
Vancouver8214.2 km- New York City8360.9 km
Mexico CIty11325.1 km
London3861.9 km
Paris3883.1 km
Berlin3008 km
Stockholm2471.7 km
Tokyo6137.1 km