Distance between Varberg and Jacksonville

The distance between Varberg (Halland County, Sweden) and Jacksonville (Florida, USA) is ca. 7.440,1 km (air line).

Varberg

Koordinaten: 57°07′N 12°13′E
Latidute: 57.10631071
Longitude: 12.25017049

Jacksonville

Latidute: 30.332184
Longitude: -81.655648

Distance between Varberg and other cities and places worldwide

Distance between Varberg and other major cities