Distance between Utebo and Waterbury

The distance between Utebo (Aragon, Spain) and Waterbury (Connecticut, USA) is ca. 5.798,7 km (air line).

Utebo

Latidute: 41.70714043
Longitude: -0.99875893

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Utebo and other cities and places worldwide

Distance between Utebo and other major cities