Distance between Sofia and Waterbury

The distance between Sofia (Bulgaria) and Waterbury (Connecticut, USA) is ca. 7.462,3 km (air line).

Sofia

Latidute: 42.698334
Longitude: 23.319941

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Sofia and other cities and places worldwide

Distance between Sofia and other major cities