Distance between Siilinjärvi and Waterbury

The distance between Siilinjärvi (North Savo, Finland) and Waterbury (Connecticut, USA) is ca. 6.459,5 km (air line).

Siilinjärvi

Koordinaten: 63°04′30″N 27°39′36″E
Latidute: 63.075
Longitude: 27.66

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Siilinjärvi and other cities and places worldwide

Distance between Siilinjärvi and other major cities