Distance between Siena and Providence

The distance between Siena (Tuscany, Italy) and Providence (Rhode Island, USA) is ca. 6.478,9 km (air line).

Siena

Koordinaten: 43°19′07″N 11°19′50″E
Latidute: 43.31861111
Longitude: 11.33055556

Providence

Latidute: 41.825226
Longitude: -71.418884

Distance between Siena and other cities and places worldwide

Distance between Siena and other major cities