Distance between Ségou and Waterbury

The distance between Ségou (Mali) and Waterbury (Connecticut, USA) is ca. 7.096,2 km (air line).

Ségou

Latidute: 13.4405971
Longitude: -6.2653221

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Ségou and other cities and places worldwide

Distance between Ségou and other major cities