The distance between Schymkent (Kazakhstan) and Jacksonville (Florida, USA) is ca. 11.414,6 km (air line).
Distance between Schymkent and other cities and places worldwide
Distance between Schymkent and other major cities
Los Angeles11482.5 km
Vancouver9755.2 km- New York City10076.5 km
Mexico CIty13048.6 km
London5184.5 km
Paris5108.2 km
Berlin4257.9 km
Stockholm3949.6 km
Tokyo5942.9 km