Distance between San Salvador and Waterbury

The distance between San Salvador (El Salvador) and Waterbury (Connecticut, USA) is ca. 3.468,2 km (air line).

San Salvador

Latidute: 13.6989
Longitude: -89.1872

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between San Salvador and other cities and places worldwide

Distance between San Salvador and other major cities