Distance between San José and Waterbury

The distance between San José (Costa Rica) and Waterbury (Connecticut, USA) is ca. 3.679,4 km (air line).

San José

Latidute: 9.9280694
Longitude: -84.0907246

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between San José and other cities and places worldwide

Distance between San José and other major cities