Distance between San José and Lexington

The distance between San José (California, USA) and Lexington (Kentucky, USA) is ca. 3.268,7 km (air line).

San José

Latidute: 37.33548
Longitude: -121.893028

Lexington

Latidute: 38.04831725
Longitude: -84.49903433

Distance between San José and other cities and places worldwide

Distance between San José and other major cities