Distance between Quito and Waterbury

The distance between Quito (Ecuador) and Waterbury (Connecticut, USA) is ca. 4.672,7 km (air line).

Quito

Latidute: -0.180654
Longitude: -78.467835

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Quito and other cities and places worldwide

Distance between Quito and other major cities