Distance between Novi Sad and Waterbury

The distance between Novi Sad (Serbia) and Waterbury (Connecticut, USA) is ca. 7.070,3 km (air line).

Novi Sad

Latidute: 45.267135
Longitude: 19.833548

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Novi Sad and other cities and places worldwide

Distance between Novi Sad and other major cities