Distance between Novi Sad and Jacksonville

The distance between Novi Sad (Serbia) and Jacksonville (Florida, USA) is ca. 8.477,7 km (air line).

Novi Sad

Latidute: 45.267135
Longitude: 19.833548

Jacksonville

Latidute: 30.332184
Longitude: -81.655648

Distance between Novi Sad and other cities and places worldwide

Distance between Novi Sad and other major cities