Distance between Maracaibo and Waterbury

The distance between Maracaibo (Venezuela) and Waterbury (Connecticut, USA) is ca. 3.438,7 km (air line).

Maracaibo

Latidute: 10.653861
Longitude: -71.645965

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Maracaibo and other cities and places worldwide

Distance between Maracaibo and other major cities