Distance between Lüneburg and Oaxaca de Juárez

The distance between Lüneburg (Lower Saxony, Germany) and Oaxaca de Juárez (Oaxaca, Mexico) is ca. 9.582,8 km (air line).

Lüneburg

Latidute: 53.24895112
Longitude: 10.41023369

Oaxaca de Juárez

Latidute: 17.06067901
Longitude: -96.72532319

Distance between Lüneburg and other cities and places worldwide

Distance between Lüneburg and other major cities