Distance between Lubusz and Thessaloniki

The distance between Lubusz (Poland) and Thessaloniki (Greece) is ca. 4.341,3 km (air line).

Lubusz

Koordinaten: 2°11′43″N 15°20′51″E
Latidute: 2.19527778
Longitude: 15.3475

Thessaloniki

Latidute: 40.629269
Longitude: 22.947412

Distance between Lubusz and other cities and places worldwide

Distance between Lubusz and other major cities