Distance between Lubusz and Sioux Falls

The distance between Lubusz (Poland) and Sioux Falls (South Dakota, USA) is ca. 11.589,9 km (air line).

Lubusz

Koordinaten: 2°11′43″N 15°20′51″E
Latidute: 2.19527778
Longitude: 15.3475

Sioux Falls

Latidute: 43.536388
Longitude: -96.731667

Distance between Lubusz and other cities and places worldwide

Distance between Lubusz and other major cities