Distance between Lubusz and San Francisco

The distance between Lubusz (Poland) and San Francisco (California, USA) is ca. 13.805,0 km (air line).

Lubusz

Koordinaten: 2°11′43″N 15°20′51″E
Latidute: 2.19527778
Longitude: 15.3475

San Francisco

Latidute: 37.773972
Longitude: -122.431297

Distance between Lubusz and other cities and places worldwide

Distance between Lubusz and other major cities