Distance between L'Aquila and Waterbury

The distance between L'Aquila (Abruzzo, Italy) and Waterbury (Connecticut, USA) is ca. 6.808,8 km (air line).

L'Aquila

Koordinaten: 42°21′N 13°24′E
Latidute: 42.35
Longitude: 13.4

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between L'Aquila and other cities and places worldwide

Distance between L'Aquila and other major cities