Distance between Juba and Waterbury

The distance between Juba (South Sudan) and Waterbury (Connecticut, USA) is ca. 10.851,4 km (air line).

Juba

Latidute: 4.85164
Longitude: 31.5824

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Juba and other cities and places worldwide

Distance between Juba and other major cities