Distance between Havana and Waterbury

The distance between Havana (Cuba) and Waterbury (Connecticut, USA) is ca. 2.226,5 km (air line).

Havana

Latidute: 23.113592
Longitude: -82.366592

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Havana and other cities and places worldwide

Distance between Havana and other major cities