Distance between Fès and Waterbury

The distance between Fès (Morocco) and Waterbury (Connecticut, USA) is ca. 5.881,6 km (air line).

Fès

Latidute: 34.0433
Longitude: -5.0033

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Fès and other cities and places worldwide

Distance between Fès and other major cities