Distance between Celle and Waterbury

The distance between Celle (Lower Saxony, Germany) and Waterbury (Connecticut, USA) is ca. 6.053,3 km (air line).

Celle

Latidute: 52.6246912
Longitude: 10.08157063

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Celle and other cities and places worldwide

Distance between Celle and other major cities