Distance between Alexandria and Waterbury

The distance between Alexandria (Egypt) and Waterbury (Connecticut, USA) is ca. 8.723,7 km (air line).

Alexandria

Latidute: 31.205753
Longitude: 29.924526

Waterbury

Koordinaten: 41°33′22″N 73°2′29″W
Latidute: 41.55611111
Longitude: -73.04138889

Distance between Alexandria and other cities and places worldwide

Distance between Alexandria and other major cities