Distance between Albany and Jacksonville

The distance between Albany (New York, USA) and Jacksonville (Florida, USA) is ca. 1.539,4 km (air line).

Albany

Latidute: 42.652581
Longitude: -73.756234

Jacksonville

Latidute: 30.332184
Longitude: -81.655648

Distance between Albany and other cities and places worldwide

Distance between Albany and other major cities