Distance between Åkersberga and Providence

The distance between Åkersberga (Stockholm County, Sweden) and Providence (Rhode Island, USA) is ca. 6.093,9 km (air line).

Åkersberga

Koordinaten: 59°29′N 18°18′E
Latidute: 59.48333333
Longitude: 18.3

Providence

Latidute: 41.825226
Longitude: -71.418884

Distance between Åkersberga and other cities and places worldwide

Distance between Åkersberga and other major cities