Population in Lake Placid compared to Schwerin
Lake Placid: 2.205 (2020)
Schwerin: 97.850 (2023)
In Lake Placid the population is about 2% of the population of Schwerin.
Size of Lake Placid compared to Schwerin
Lake Placid: ca. 4 km²
Schwerin: ca. 130 km²
Lake Placid has a land area approximately 97% smaller than Schwerin
Population density of Lake Placid compared to Schwerin
Lake Placid: ca. 1.620 Einwohner/km²
Schwerin: ca. 750 Einwohner/km²
The population density of Lake Placid is about2.2 times higher, than the one of Schwerin.
City comparison between Lake Placid and other cities
more about Lake Placid (New York, USA)
more about Schwerin (Mecklenburg-Vorpommern, Germany)